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MITTIE Betty Mitchell Houk

Female 1897 -


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Generation: 1

  1. 1.  MITTIE Betty Mitchell Houk was born on 24 Jul 1897 in AUBREY, TX.

    Family/Spouse: William Alvin Thomas. William was born on 03 Oct 1885 in LITTLE ELM, TX; died on 02 Apr 1974. [Group Sheet] [Family Chart]

    Children:
    1. 2. William Ira Thomas  Descendancy chart to this point
    2. 3. Annie Lorice Thomas  Descendancy chart to this point


Generation: 2

  1. 2.  William Ira Thomas Descendancy chart to this point (1.Betty1)

    William married OLGA EMELIA GORSKI [Group Sheet] [Family Chart]

    Children:
    1. 4. WILLIAM STEPHEN THOMAS  Descendancy chart to this point

  2. 3.  Annie Lorice Thomas Descendancy chart to this point (1.Betty1)

    Annie married Neal C Hays [Group Sheet] [Family Chart]

    Children:
    1. 5. Amelia Anne Hays  Descendancy chart to this point
    2. 6. Thomas Neal Hays  Descendancy chart to this point


Generation: 3

  1. 4.  WILLIAM STEPHEN THOMAS Descendancy chart to this point (2.William2, 1.Betty1)

    WILLIAM married GLENDA GAIL BAKER [Group Sheet] [Family Chart]

    Children:
    1. 7. JULIE LEIGH THOMAS  Descendancy chart to this point
    2. 8. WILLIAM DAVID THOMAS  Descendancy chart to this point

  2. 5.  Amelia Anne Hays Descendancy chart to this point (3.Annie2, 1.Betty1)

    Amelia married Bill R Alland [Group Sheet] [Family Chart]

    Children:
    1. 9. TOBIN MICHAEL ALLAND  Descendancy chart to this point
    2. 10. MILANIE KRISTIN ALLAND  Descendancy chart to this point

  3. 6.  Thomas Neal Hays Descendancy chart to this point (3.Annie2, 1.Betty1)

    Thomas married CARRIE VIRGINIA JOHNSON [Group Sheet] [Family Chart]



Generation: 4

  1. 7.  JULIE LEIGH THOMAS Descendancy chart to this point (4.WILLIAM3, 2.William2, 1.Betty1)

  2. 8.  WILLIAM DAVID THOMAS Descendancy chart to this point (4.WILLIAM3, 2.William2, 1.Betty1)

  3. 9.  TOBIN MICHAEL ALLAND Descendancy chart to this point (5.Amelia3, 3.Annie2, 1.Betty1)

  4. 10.  MILANIE KRISTIN ALLAND Descendancy chart to this point (5.Amelia3, 3.Annie2, 1.Betty1)


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